急!!!數學歸納法問題一條!!高手幫幫忙!明早要!

2010-05-07 7:10 am
Prove that 11(14^n) +1 is composite for all positive integers n.

老師有說要弄2個CASE. 1個ODD,1個EVEN.
請幫忙!

回答 (1)

2010-05-07 7:50 am
✔ 最佳答案
For n = 1 ,
11(14) + 1 = 5 x 31 is true ,
For n = 2 ,
11(14^2) + 1 = 3 x 719 is true ,
Assume that when n = k is odd ,
11(14^k) + 1 = 5T were T is an integer ;
when n = k is even ,
11(14^k) + 1 = 3V were V is an integer ,
when n = k+2 ,
11(14^(k+2)) + 1
= (14^2) * 11(14^k) + 1
= (14^2 - 1) * 11(14^k) + 11(14^k) + 1
= (3 * 5 * 13) * 11(14^k) + (5 T or 3 V)
So it is true for all integers.


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