let b, m, n are some natural numbers
b is bigger than 1
m and n are not equal
b^m - 1 and b^n - 1 have the same set of prime divisors
show that
b + 1 = 2^k
(where k is a natural mumber)
please give me some hints how to show that b is odd
and m = 2, n = 1
or
slove the question
給我一些hints(數論)
2010-05-06 1:27 am
回答 (1)
2010-05-11 4:44 am
✔ 最佳答案
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2010-05-10 20:44:42 補充：
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收錄日期: 2021-04-11 14:53:32
原文連結 [永久失效]:
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