Given: Specific heat capacity of water = 4200 J/kg/oC
Specific latent heat of fusion of ice/water = 334000 J/kg
Specific latent heat of vaporization of water/steam = 2260000 J/kg
Specific heat capacity of ice below 0 oC = 2100 J/kg/oC
Specific heat capacity of steam above 100 oC = 2100 J/kg/oC
1. A piece of 10 g ice at 0 oC is dropped into a cup of 0.1 kg water at 70 oC. Find the temperature of the final mixture.
2. A piece of 0.1 kg ice at 0 oC is dropped into a cup of 0.1 kg water at 50
oC. Find the temperature of the final mixture. Find also the amount of ice melted if the ice dose not completely melt.
F.3 Physics-change of state20分
2010-05-04 4:52 am
回答 (2)
2010-05-04 5:39 am
✔ 最佳答案
1. Let T be the final temperature.Hence, using the heat balance equation,
(10/1000) x 334000 + (10/1000) x 4200 x (T) = 0.1 x 4200 x (70-T)
solve for T gives T = 56.4'C
2. Heat given out by water = 0.1 x 4200 x 50 J = 21000 J
Heat absorbed by ice = m x 334000 J = 334000m J
where m is the mass of ice melted
Hence, 334000m = 21000
m = 0.063 kg
Since not all of the ice has melted, the final temperature of the mixture is clearly at 0'C
2010-05-04 5:15 am
1.54度？????!
2010-05-03 21:18:50 補充：
2.the temperature of the final mixture=0度??
the amount of ice melted=0.0625kg???
2010-05-03 21:18:50 補充：
2.the temperature of the final mixture=0度??
the amount of ice melted=0.0625kg???
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