Evaluate the polynomial x2+ 2y2- 3xy for x = 3 and y = 4?
回答 (9)
2010-05-01 1:12 pm
✔ 最佳答案
Its 3^2+2*4^2-3*3*4=9+32-36= 5.
2016-06-02 5:29 pm
just put the values of x & y u get 5*(-3) - 4 = -19 answer is -19 i.e A
2010-05-01 3:01 pm
9+2(16)-3(3)(4)
9+32-36 = 5
9+32-36 = 5
2010-05-01 12:45 pm
x^2 + 2y^2 - 3xy
(x = 3, y = 4)
Substitute 3 and 4 for x and y respectively.
3^2 + 2(4)^2 - 3(3)(4)
= 9 + 2(16) - 9(4)
= 9 + 32 - 36
= 5
(x = 3, y = 4)
Substitute 3 and 4 for x and y respectively.
3^2 + 2(4)^2 - 3(3)(4)
= 9 + 2(16) - 9(4)
= 9 + 32 - 36
= 5
2010-05-01 12:36 pm
x² + 2y² – 3xy
= x² – 3xy + 2y²
= x² – 2xy – xy + 2y²
= x(x – 2y) – y(x – 2y)
= (x – 2y) (x – y)
= (3 – 8)(3 – 4)
= (–5)(– 1)
= 5
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= x² – 3xy + 2y²
= x² – 2xy – xy + 2y²
= x(x – 2y) – y(x – 2y)
= (x – 2y) (x – y)
= (3 – 8)(3 – 4)
= (–5)(– 1)
= 5
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2010-05-01 12:33 pm
Well I assume you mean
x^2+2y^2-3xy
3^2+2*4^2-3*3*4
9+32-36=5
x^2+2y^2-3xy
3^2+2*4^2-3*3*4
9+32-36=5
2010-05-01 12:27 pm
x2+ 2y2- 3xy = 3^2 + 2*4^2 - 3*3*4 = 9+32-36 = 5
2010-05-01 12:27 pm
(3)^2+2(4)^2-3(3)(4)
9+2(16)-9(4)
9+32-36
9-4
5
9+2(16)-9(4)
9+32-36
9-4
5
2010-05-01 12:26 pm
3^2 + 2*4^2 - 3(3)(4) =
9 + 32 - 36 =
5
9 + 32 - 36 =
5
收錄日期: 2021-05-01 13:03:16
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