列式&解&步驟。
更新1:
求高度和面積
等邊三角形
回答 (4)
2010-05-07 6:52 am
2010-05-05 11:43 pm
2010-05-02 5:42 am
Let h be the height of the triangle,
sin 60=h/4
h=4sin60=2√3
the height of the triangle is 2√3cm
2010-05-01 21:45:40 補充：
You can also use Pythagoras' theorem.
2010-05-01 21:47:45 補充：
h^2=4^2-2^2=12 (Pyth. theorem)
h=2√3
h=3.46(corr. to 3 sig. fig.)
2010-05-01 21:55:16 補充：
Area of the triangle
=0.5x4x2√3
=4√3cm^2
sin 60=h/4
h=4sin60=2√3
the height of the triangle is 2√3cm
2010-05-01 21:45:40 補充：
You can also use Pythagoras' theorem.
2010-05-01 21:47:45 補充：
h^2=4^2-2^2=12 (Pyth. theorem)
h=2√3
h=3.46(corr. to 3 sig. fig.)
2010-05-01 21:55:16 補充：
Area of the triangle
=0.5x4x2√3
=4√3cm^2
2010-05-02 5:38 am
高度²=4²-2²
=16-4
=12
高度=開方12
=2開方3 cm
2010-05-01 21:39:36 補充：
http://j.imagehost.org/0121/ScreenHunter_01_May_01_21_35.gif
2010-05-01 22:26:42 補充：
面積=1/2(4)²sin60
=4開方3cm²
=16-4
=12
高度=開方12
=2開方3 cm
2010-05-01 21:39:36 補充：
http://j.imagehost.org/0121/ScreenHunter_01_May_01_21_35.gif
2010-05-01 22:26:42 補充：
面積=1/2(4)²sin60
=4開方3cm²
收錄日期: 2021-04-23 20:40:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100501000051KK01697