magnetism

2010-04-28 1:23 pm

1)Find
圖片參考:http://session.masteringphysics.com/render?tex=%7B%5Crm+cm%7D
-radius semicircle in the figure .
The straight wires extend a great distance outward to the left and
carry a current
圖片參考:http://session.masteringphysics.com/render?texml=I+%3D+5.6+%5C%2C+%5Crm+A
.
Express your answer using two significant
figures.




圖片參考:http://imgcld.yimg.com/8/n/HA00021001/o/701004280015413873388340.jpg

ans:


圖片參考:http://session.masteringphysics.com/render?var=B

= 5.9×10−5

圖片參考:http://session.masteringphysics.com/render?tex=%5Crm+T


2.J. J. Thomson is best known for his discoveries about the nature of
cathode rays. Another important contribution of his was the invention,
together with one of his students, of the mass spectrometer. The ratio
of mass
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to (positive) charge

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of an ion may be accurately determined in a mass
spectrometer. In essence, the spectrometer consists of two regions: one
that accelerates the ion through a potential
圖片參考:http://session.masteringphysics.com/render?var=V
and a second that measures its radius of curvature in a
perpendicular magnetic field.
The ion begins at potential
圖片參考:http://session.masteringphysics.com/render?var=V
and is accelerated toward zero potential. When the
particle exits the region with the electric field it will have obtained a
speed
圖片參考:http://imgcld.yimg.com/8/n/HA00021001/o/701004280015413873388341.jpg


a)With what speed
圖片參考:http://session.masteringphysics.com/render?var=u
does the ion exit the acceleration region?
Find the speed in terms of
圖片參考:http://session.masteringphysics.com/render?var=V
, and any constants.






圖片參考:http://session.masteringphysics.com/render?var=u

=
圖片參考:http://session.masteringphysics.com/render?tex=%5Csqrt%7B%5Cfrac%7BqV2%7D%7Bm%7D%7D

b)After being accelerated, the particle enters a
uniform magnetic field of strength
圖片參考:http://session.masteringphysics.com/render?var=R
(determined by observing where it hits on a screen--as
shown in the figure). The results of this experiment allow one to find
圖片參考:http://session.masteringphysics.com/render?tex=m%2Fq
in terms of the experimentally measured
quantities such as the particle radius, the magnetic field, and the
applied voltage.
What is
圖片參考:http://session.masteringphysics.com/render?tex=m%2Fq
?
Express
圖片參考:http://session.masteringphysics.com/render?var=R
, and any necessary constants.






圖片參考:http://session.masteringphysics.com/render?tex=m%2Fq

=
圖片參考:http://session.masteringphysics.com/render?tex=B_%7B0%7D%7B%5E%7B2%7D%7D%5Cfrac%7BR%5E%7B2%7D%7D%7B2V%7D


i just confuse where the number 2 came from




回答 (1)

2010-04-28 5:24 pm
✔ 最佳答案
1. By right-hand-grip rule, the magnetic field at B should point into the paper.

Magnetic field due to the two long straight wires, B'

= 2 X u0I/4pir = u0I/2pir

Magnetic field due to the semi-circular arc, B"

= u0I/2r

So, the magnetic field at B = B' + B" = (4pi X 10^-7)(5.6)/2(0.049) [1 + 1/pi]

= 9.5 X 10^-5 T

Your answer is wrong.


2. By energy conservation, the electric potential energy loss = Gain in K.E.

So, K.E., 1/2 mu^2 = qV

Speed, u = sqrt(2qV/m)

b. After entering the magnetic field, the speed of the particle is unchanged.

it will experience a magnetic force, which accounts for the centripetal force.

mu^2 / R = quB0

m/q = RB0/u = RB0/sqrt(2qV/m)

sqrt(m/q) = RB0/sqrt(2V)

So, m/q = R^2B0^2 / 2V
參考: Physics king


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