Multiply (3x – 2)^2.?

The answer is B.
.because by using the FOIL (FIRST,OUTER,INNER,LAST) method you can get the answer..

(3x – 2)^2
=9x^2-12x+4

1) 3x(3x-2)-2(3x-2)
2 )9x^2 - 6x - 6x + 4
3) 9x^2 - 12x + 4

Your answer is B

(3x - 2)(3x - 2)
9x^2 - 6x - 6x + 4

B. 9x^2 - 12x + 4 is the final answer

It's A.
First you take (3x-2) (3x-2)
Then you times 3x by 3x which gives you 9x^2.
Next you take -2 x -2= 4 because a negative times a negative equals a positive.

ok, you should use FOIL for this, it helps =]
First terms, Outside terms, Inside terms, and Last terms
so... (3x-2)*(3x-2)= 9x^2+-6x+-6x-(-4)
this equals= 9x^2+-12x+4
the answer is B
I hope this helps =D

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2(5x+3)=3x-22 Start with multiplying 2 times 5x and +3( 10x +6= 3x-22 ) 10x +6= 3x-22 minus 3x from both sides 10x -3x = 7x 3x -3x 0 ( 7x+6 = -22 ) 7x+6 = -22 minus 6 from both sides +6 and -6 =0 -22 -6 =-28 (7x =-28) 7x =-28 divide both sides by 7 7x/7 = x -28/7 =4 (x=-4) answer is x=-4 It is nice to have someone do it for you, but you must learn how or fail the test! Good Luck!

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RE:
Multiply (3x – 2)^2.?
Multiply (3x – 2)^

( 3x - 2) ( 3x - 2) = 9 x ² - 12 x + 4

OPTION B

B is correct...
Use formula:
.... ( a - b )^2 = ( a )^2 - 2(a)(b) + ( b )^2
In ( 3x - 2 )^2 ............ a = 3x and b = 2,, now put these in the formula,
....( 3x - 2 )^2 = ( 3x)^2 - 2(3x)(2) + ( 2 )^2
....( 3x - 2 )^2 = 9x^2 - 12x + 4

(a-b)^2 = a^2 - 2ab + b^2

(3x-2)^2 = (3x)^2 -2(3)(2)x +2^2

= 9x^2 -12x+ 4

Ans B