求救!
Use Newton's <ethod to determine the root of the equation e^-x+sinx-0.5=0.
Start with x=2 and give answer correct to five decimal places.
數學 Newton's method
2010-04-17 10:17 am
回答 (1)
2010-04-17 4:19 pm
✔ 最佳答案
Let f(x) = e^-x + sinx - 0.5f'(x) = -e^-x + cosx
By Newton's method, xn+1 = xn - f(xn)/f'(xn)
With initial guess x0 = 2,
x1 = 2.987579997
x2 = 2.702394196
x3 = 2.694431263
x4 = 2.694419475
x5 = 2.694419475
So, to 5 d.p., x = 2.69442
參考: Physics king
收錄日期: 2021-04-19 21:53:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100417000051KK00165