請幫忙數學列式--急

2010-04-17 4:13 am
1) Linda bought a doll with 7/12of her money and a box of chocolates with 2/5 of the remainder of her money. Ifshe spent $10 on the box of chocolates, how much more did she spend on the doll?
2) Mrs. Lam had $80. She spent 3/16 of it on a magazine and 3/5 of the remainder ona bag. How much money had she left?
3) Aaron has 3/4 asmany bluemarbles as green marbles . If he has 42 blue and green marbles together, how many blue marbles does he have?

回答 (3)

2010-04-17 4:53 am
✔ 最佳答案
1)
Price of the doll : Price of chocolate
=(7/12) : [1−(7/12)](2/5)
= 7:2

∴Price of the doll = 10(7/2) = $35



2)
Money she left
= 80[1−(3/16)][1−(3/5)]
= $26

3)
Number of blue marbles : Number of green marbles
= (3/4):1
= 3:4

Number of blue marbles = 42(3/7) = 18
2010-04-17 6:42 pm
第3題唔明白為什麼是3/4:1, 又為什麼是42(7/4)
2010-04-17 4:16 am
3) Aaron has 3/4 as many blue marbles as green marbles . If he has 42 blue and green marbles together, how many blue marbles does he have?

I don't understand...


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