Deduce the formula( may be it cannot deduce) is true for all positive integers n
a. 1*2+3*4+5*6+7*8+...+(2n-1)(2n)
b. 1/(2-2^(0.5))+1/(5^(0.5)-3^(0.5))+1/(6^(0.5)-2)+...+1/((n+3)^(0.5)+(n+1)^0.5))
c. n*1+(n-1)*3+(n-2)*5+....+1*(2n-1)
d. 2*3*4+3*4*7+4*5*12+...+(n+1)(n+2)((n^2)+3)
e.2*2+5*4+10*8+.....+((n^2)+1)(2^n)
f.4 M2 M.I. deduce a formula
2010-04-14 6:35 am
回答 (4)
2010-04-15 6:08 am
✔ 最佳答案
======================================================圖片參考：http://img199.imageshack.us/img199/3644/22047416.png
圖片參考：http://img188.imageshack.us/img188/4866/35603280.png
2010-04-14 22:08:52 補充：
http://img199.imageshack.us/img199/3644/22047416.png
http://img188.imageshack.us/img188/4866/35603280.png
2010-04-14 8:38 pm
Yes 搵番條式出黎
2010-04-14 8:34 pm
題主係咪要搵番條式出黎?
2010-04-14 3:04 pm
a. 1*2+3*4+5*6+7*8+...+(2n-1)(2n) = ?
b. 1/(2-2^(0.5))+1/(5^(0.5)-3^(0.5))+1/(6^(0.5)-2)+...+1/((n+3)^(0.5)+(n+1)^0.5)) =?
c. n*1+(n-1)*3+(n-2)*5+....+1*(2n-1) =?
d. 2*3*4+3*4*7+4*5*12+...+(n+1)(n+2)((n^2)+3)=?
e.2*2+5*4+10*8+.....+((n^2)+1)(2^n)=?
b. 1/(2-2^(0.5))+1/(5^(0.5)-3^(0.5))+1/(6^(0.5)-2)+...+1/((n+3)^(0.5)+(n+1)^0.5)) =?
c. n*1+(n-1)*3+(n-2)*5+....+1*(2n-1) =?
d. 2*3*4+3*4*7+4*5*12+...+(n+1)(n+2)((n^2)+3)=?
e.2*2+5*4+10*8+.....+((n^2)+1)(2^n)=?
收錄日期: 2021-04-23 23:22:40
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