F.4 數學 20 分 急!!

2010-04-11 8:50 pm

回答 (2)

2010-04-12 1:46 am
5.
Let OP=x, PC=13-x
(5)(5)=(13+x)(13-x)
x=12
AP=13+x
AP=25
AD^2=5^2+25^2
AD=25.495
因为三角形ADP全等于三角形ABP
所以AB=AD=25.495
三角形ABD的周界=(2)(25.495)+(2)(5)=61.0


7.
Let angle CBP=2x, and angle ACB=3x
2x+3x=65°
x=13°
angle ACB=3X=39°


9.
angle ADB=angle BCA=48°(共弦)
angle CAD=angle ADB=48° (BD//TS)
angle ACD=angle SAD=48°


11.
connect AC
angle ACB=angle BAQ=20°
angle OAC=angle ACB=20°(AO//CB)
since OA=OC
angle OCA=angle OAC=20°
angle BCO=20°+20°=40°


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