A heater transfer 500 kj of energy to some water at 30C . If the heat capacity of he water is 10000J C^-1 ,what is the temperature of the water after heating?
steps please!
physics!
2010-04-02 11:23 pm
回答 (3)
2010-04-03 3:36 am
2010-04-02 11:44 pm
Rise in temperature = 500 x 10^3/10000 'C = 50'C
Hence, the final temperature of water = (30 + 50)'C = 80'C
Hence, the final temperature of water = (30 + 50)'C = 80'C
2010-04-02 11:31 pm
32C......................................
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