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2010-04-02 9:49 pm
1.log2 1/2 + log2 2/3 +log2 3/4 = ?

2.f(x) = 2x的2次方 + 3x + k 此公式被x+1整除 求k?

3.x的2次方 + 5x + 2 = 0

4.(6x的2次方 + 4x + 6)+(6x的3次方 + 10x + 1) = ?





需要完整公式~
3q3q~ =)
更新1:

^ 這是什麼阿? =)

回答 (1)

2010-04-02 10:18 pm
✔ 最佳答案
1.
log2(1/2) + log2(2/3) + log2(3/4)
= log2[(1/2)•(2/3)•(3/4)]
= log2(1/4)
= log2(2)^-2
= -2log2(2)
= -2


2.
f(x) = 2x² + 3x + k 能被 x + 1 整除,
f(-1) = 0
2(-1)² + 3(-1) + k = 0
2 - 3 + k = 0
k = 1


3.
x² + 5x + 2 = 0
x = {-5 ±√[(5)² - 4(1)(2)]}/2
x = (-5 + √17)/2 或 x = (-5 - √17)/2


4.
(6x² + 4x + 6) + (6x³ + 10x + 1)
= 6x² + 4x + 6 + 6x³ + 10x + 1
= 6x³ + 6x² + 14x + 7

2010-04-04 08:07:59 補充:
^ 代表次方。
例如 3^2 = 3² = 9
參考: 胡雪八


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