Factoring...can you solve these?

The first one is (7x + 5) (x - 1)
The second one is (3x - 8) (x + 1)
The third one is (3x - 8) (2x + 1)
I hope this helps! :) Good luck.

1)
7x^2 - 2x - 5
= 7x^2 + 5x - 7x - 5
= (7x^2 + 5x) - (7x + 5)
= x(7x + 5) - 1(7x + 5)
= (7x + 5)(x - 1)

2)
3x^2 - 5x - 8
= 3x^2 + 3x - 8x - 8
= (3x^2 + 3x) - (8x + 8)
= 3x(x + 1) - 8(x + 1)
= (x + 1)(3x - 8)

3)
6x^2 - 13x - 8
= 6x^2 + 3x - 16x - 8
= (6x^2 + 3x) - (16x + 8)
= 3x(2x + 1) - 8(2x + 1)
= (2x + 1)(3x - 8)

7x^2 - 2x - 5
Factors: (7x+5)(x-1)

3x^2 - 5x - 8
Factors: (3x-8)(x+1)

6x^2 - 13x -8
Factors: (3x -8)(2x+1)

7x^2 - 2x - 5 = (7x + 5)(x - 1)
3x^2 - 5x - 8 = (3x - 8)(x + 1)
6x^2 - 13x - 8 = (3x - 8)(2x + 1)
Use trial and error.

(7x+5)(x-1)

(3x-8)(x+1)

(3x-8)(2x+1)

7x²-2x-5
(-7x-5)(-x+1)

3x²-5x-8
(-x-1)(-3x+8)

6x²-13x-8
(-2x-1)(-3x+8)