7x^2 - 2x - 5
3x^2 - 5x - 8
6x^2 - 13x -8
Factoring...can you solve these?
2010-04-01 5:44 pm
回答 (6)
2010-04-01 5:50 pm
✔ 最佳答案
The first one is (7x + 5) (x - 1)The second one is (3x - 8) (x + 1)
The third one is (3x - 8) (2x + 1)
I hope this helps! :) Good luck.
2010-04-02 1:51 am
1)
7x^2 - 2x - 5
= 7x^2 + 5x - 7x - 5
= (7x^2 + 5x) - (7x + 5)
= x(7x + 5) - 1(7x + 5)
= (7x + 5)(x - 1)
2)
3x^2 - 5x - 8
= 3x^2 + 3x - 8x - 8
= (3x^2 + 3x) - (8x + 8)
= 3x(x + 1) - 8(x + 1)
= (x + 1)(3x - 8)
3)
6x^2 - 13x - 8
= 6x^2 + 3x - 16x - 8
= (6x^2 + 3x) - (16x + 8)
= 3x(2x + 1) - 8(2x + 1)
= (2x + 1)(3x - 8)
7x^2 - 2x - 5
= 7x^2 + 5x - 7x - 5
= (7x^2 + 5x) - (7x + 5)
= x(7x + 5) - 1(7x + 5)
= (7x + 5)(x - 1)
2)
3x^2 - 5x - 8
= 3x^2 + 3x - 8x - 8
= (3x^2 + 3x) - (8x + 8)
= 3x(x + 1) - 8(x + 1)
= (x + 1)(3x - 8)
3)
6x^2 - 13x - 8
= 6x^2 + 3x - 16x - 8
= (6x^2 + 3x) - (16x + 8)
= 3x(2x + 1) - 8(2x + 1)
= (2x + 1)(3x - 8)
2010-04-02 12:52 am
7x^2 - 2x - 5
Factors: (7x+5)(x-1)
3x^2 - 5x - 8
Factors: (3x-8)(x+1)
6x^2 - 13x -8
Factors: (3x -8)(2x+1)
Factors: (7x+5)(x-1)
3x^2 - 5x - 8
Factors: (3x-8)(x+1)
6x^2 - 13x -8
Factors: (3x -8)(2x+1)
2010-04-02 12:51 am
7x^2 - 2x - 5 = (7x + 5)(x - 1)
3x^2 - 5x - 8 = (3x - 8)(x + 1)
6x^2 - 13x - 8 = (3x - 8)(2x + 1)
Use trial and error.
3x^2 - 5x - 8 = (3x - 8)(x + 1)
6x^2 - 13x - 8 = (3x - 8)(2x + 1)
Use trial and error.
2010-04-02 12:50 am
(7x+5)(x-1)
(3x-8)(x+1)
(3x-8)(2x+1)
(3x-8)(x+1)
(3x-8)(2x+1)
2010-04-02 12:49 am
7x²-2x-5
(-7x-5)(-x+1)
3x²-5x-8
(-x-1)(-3x+8)
6x²-13x-8
(-2x-1)(-3x+8)
(-7x-5)(-x+1)
3x²-5x-8
(-x-1)(-3x+8)
6x²-13x-8
(-2x-1)(-3x+8)
收錄日期: 2021-05-01 13:02:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100401094429AAvxZaP