物理phy~~~~~~~

Two objects have same density D.
Let volume of X and Y be Vx and Vy.
Let mass of X and Y be Mx and My.
Pressure = Force / Area
In the case of P1 and P2, the contact area is A and 2A respectively
D = Mx/Vx = My/Vy
Vx = 2Vy
Mx = 2My
P1 = Myg / A
P2 = (Mx+My)g / A = 3Myg/2A = 3/2 P1
P1:P2 = 1: 1.5 = 2:3------>Ans:D//

Let m be the mass of brick X, and M be the mass of brick Y, Since pressure = thrust/area,
hence, P1 = mg/A
where A is the base area of brick X, and g is the acceleration due to gravity
P2 = (m+M)g/2A

P1/P2 = (mg/A)/[(M+m)g/2A] = m/(M+m)
but mass = density x volume
hence, m = (d).(A.L), and (M+m) = d.(A.L + 2A.L) = 3d.A.L
where d is the density of brick ma d L is the thickness of the brick

Therefore, P1/P2 = d.A.L/3.d.A.L = 1/3 = 1:3