how to solve 3x^2=-9x?
回答 (5)
2010-03-31 4:11 pm
✔ 最佳答案
3x^2=-9x3x^2+9x=0
3x(x+3)=0
3x=0 x+3=0
..........x=-3
x=0,-3 answer//
2010-03-31 5:03 pm
3x^2 = -9x
3x^2 + 9x = 0
3x(x + 3) = 0
3x = 0
x = 0
x + 3 = 0
x = -3
∴ x = -3, 0
3x^2 + 9x = 0
3x(x + 3) = 0
3x = 0
x = 0
x + 3 = 0
x = -3
∴ x = -3, 0
2010-03-31 4:09 pm
3x^2+9x=0
x(3x+9)=0
if 3x=0 and the x is 0
if 3x+9=0 and the x is -3
x(3x+9)=0
if 3x=0 and the x is 0
if 3x+9=0 and the x is -3
2010-03-31 4:01 pm
3x² = -9x
3x² + 9x = 0
3x(x+3) = 0
3x = 0 or x+3 = 0
x=0 or x=-3
3x² + 9x = 0
3x(x+3) = 0
3x = 0 or x+3 = 0
x=0 or x=-3
2010-03-31 4:00 pm
3x^2 = -9x
Pass the 9x to the left side
3x^2 + 9x = 0
3x is a common factor
3x (x + 3) = 0
Now you have two possible solutions:
a) 3x = 0 and therefore x = 0
b) x + 3 = 0 and therefore x = -3
Pass the 9x to the left side
3x^2 + 9x = 0
3x is a common factor
3x (x + 3) = 0
Now you have two possible solutions:
a) 3x = 0 and therefore x = 0
b) x + 3 = 0 and therefore x = -3
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