how would i divide this...4x^2 / -3x^4 ?

4x^2 / - 3x^4
=4 / - 3x^2
= - 4/3 * x^-2

okay so you do order of operations (2-5)= -3 then square it and you get 9 then use order of operations and it would be 9 divided by 3 = 3, x 4 = 12.

4x²÷ -3x^4

(4x)(4X)
----------------------
(-3x)(3x)(3x)(3x)

(x+x+x+x)(x+x+x+x)
---------------------------
(-x+-x+-x)(x+x+x)(x+x+x)(x+x+x)

x²/-3x²



ANSWER: x²/-3x²

=-(4/3) x^-2=
=-4/(3x^2)
God bless you.

- 4 x ²
------------
3 x^4

- 4
---------
3 x ²

4x^2/(-3x^4)
= [4/(-3)][x^2/(x^4)]
= [-4/3][1/(x^2)]
= -4/(3x^2)

4x^2/-3x^4 -4/3x^2

4x^2 / -3x^4
I think this is the answer

= -4 / 3x^2 ans..

if you wrote this the long way it would be (4xx)/ (-3xxxx)

cross out what's common on top and below and you end up with -4/3x^2

Okay, You can move the (-4/3) out in front and you get

(-4/3) * (x^2/x^4)

To divide exponents you find the difference between them and put it wherever the highest exponent was.
So, x^2/x^4 = 1/x^2.

The answer is

4/-3x^2