Simplifying an algebraic expression?

you want to make the fractions so that they have the same denominator, then you can add them.

so if you multiplied the first one by a/a (this equals one, so it won't change the value of the fraction), you would get 5a^2/2ab
and if you multiplied the second one by b/b, you would get 3b^2/2ab

so now we have 5a^2/2ab + 3b^2/2ab
since they have the same denominator, you can just add the numerators:

= (5a^2 + 3b^2)/2ab

5a/2b + 3b/2a

=5a/2b * a/a + 3b/2a *b/b

= 5a^2 /2ab + 3b^2 / 2ab

= (5a^2 +3b^2 ) / 2ab

5a/(2b) + 3b/(2a)
= (5a * a)/(2b * a) + (3b * b)/(2a * b)
= 5a^2/(2ab) + 3b^2/(2ab)
= (5a^2 + 3b^2)/(2ab)

5a/2b + 3b/2a

=5a/2b * a/a + 3b/2a *b/b

= 5a^2 /2ab + 3b^2 / 2ab

= (5a^2 +3b^2 ) / 2ab

I believe you get a common denominator, so you would do
5a*a/2b*a + 3b*b/2a*b
(5a^2+3b^2)/2ab
that's the best I can do

Question can be MISREAD in a number of ways due to lack of brackets.

Will have to GUESS that you mean :-

5a / (2b) + 3b / (2a)

5 a ² + 3 b ²
----------------
2a b