中二數學主項變換
回答 (6)
2010-03-26 6:43 pm
( p + r ) a + ( p - r ) b = 0 [p]
ap + ar + bp - br = 0
ar - br = ap + bp
( a - b ) r = ( a + b ) p
( a - b ) r / ( a + b ) = p
p = ( a - b ) r / ( a + b )
ap + ar + bp - br = 0
ar - br = ap + bp
( a - b ) r = ( a + b ) p
( a - b ) r / ( a + b ) = p
p = ( a - b ) r / ( a + b )
2010-03-26 11:22 am
以本人有限旳知識黎睇.. 5個答案中得頭同尾兩個岩架咋 發問者請小心選擇
2010-03-26 7:42 am
(p+r)a+(p-r)b=0
ap + ar + bp - br = 0
p(a + b) = br - ar
p(a + b) = (br - ar) / (a + b)
2010-03-25 23:43:44 補充：
唔記得del番!
(p+r)a+(p-r)b=0
ap + ar + bp - br = 0
p(a + b) = br - ar
p = (br - ar) / (a + b)
ap + ar + bp - br = 0
p(a + b) = br - ar
p(a + b) = (br - ar) / (a + b)
2010-03-25 23:43:44 補充：
唔記得del番!
(p+r)a+(p-r)b=0
ap + ar + bp - br = 0
p(a + b) = br - ar
p = (br - ar) / (a + b)
2010-03-26 6:02 am
(p+r)a+(p-r)b=0
ap+ar+bp-br=0
ar-br=ap+bp
(a-b)r=(a+b)p
(a-b)r/(a+b)=p
p=(a-b)r/(a+b)
ap+ar+bp-br=0
ar-br=ap+bp
(a-b)r=(a+b)p
(a-b)r/(a+b)=p
p=(a-b)r/(a+b)
參考: me
2010-03-26 5:29 am
(p+r)a+(p-r)b=0
pa+ar+bp+br=0
p(a+b)+r(a+b)=0
(a+b)(p+r)=0
p+r=1/(a+b)
p=(1/(a+b))-r
2010-03-25 23:08:23 補充：
錯左,更正返
(p+r)a+(p-r)b=0
ap+ar+bp-br=0
p(a+b)+r(a-b)=0
p(a+b)-r(a+b)=0
(p-r)(a+b)=0
p-r=0/(a+b)
p-r=0
p=r
pa+ar+bp+br=0
p(a+b)+r(a+b)=0
(a+b)(p+r)=0
p+r=1/(a+b)
p=(1/(a+b))-r
2010-03-25 23:08:23 補充：
錯左,更正返
(p+r)a+(p-r)b=0
ap+ar+bp-br=0
p(a+b)+r(a-b)=0
p(a+b)-r(a+b)=0
(p-r)(a+b)=0
p-r=0/(a+b)
p-r=0
p=r
2010-03-26 5:00 am
(p+r)a+(p-r)b=0 [p]
pa+ra+pb-rb=0
pa+pb=rb-ra
p(a+b)=r(b-a)
p=r(b-a) /(a+b)
p= r (a+b) / (a-b)
p=ra+rb / a-b
Hope I can help you!
2010-03-26 16:51:06 補充：
忘了加括號
答案是r(a+b)/a-b
才對。
pa+ra+pb-rb=0
pa+pb=rb-ra
p(a+b)=r(b-a)
p=r(b-a) /(a+b)
p= r (a+b) / (a-b)
p=ra+rb / a-b
Hope I can help you!
2010-03-26 16:51:06 補充：
忘了加括號
答案是r(a+b)/a-b
才對。
參考: 自己
收錄日期: 2021-04-13 17:10:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100325000051KK01314