(2^x+6) - (8^2x-3) = 0
With full step,
Solve the following equations
Maths question
2010-03-26 4:00 am
回答 (2)
2010-03-26 4:14 am
✔ 最佳答案
(2^x+6) - (8^2x-3) = 02 ^ (x+6) = 8 ^ (2x-3)
2 ^ (x+6) = (2^3) ^ (2x-3)
2 ^ (x+6) = 2 ^ 3(2x-3)
x+6 = 3(2x-3)
x+6 = 6x - 9
5x = 15
x = 3
2010-03-26 4:18 am
(2^x+6)-(8^2x-3)=0
(2^x+6)-[2^(3)2x-3]=0
2^x+6=2^6x-9
x+6=6x-9
6x-x=6+9
5x=15
x=3
(2^x+6)-[2^(3)2x-3]=0
2^x+6=2^6x-9
x+6=6x-9
6x-x=6+9
5x=15
x=3
收錄日期: 2021-04-15 23:34:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100325000051KK01206