chem question

The answer is D.

Lead(II) nitrate is soluble in water. Therefore, lead(II) chloride can be prepared by mixing lead(II) nitrate solution and dilute hydrochloric acid, and the lead(II) chloride precipitate formed can be separated from the reaction mixture by filtration.
Pb(NO3)2(aq) + 2HCl(aq) → PbCl2(s) + 2HNO3(aq)
or: Pb^2+(aq) + 2Cl^-(aq) → PbCl2(s)

Lead, Lead(II) carbonate and lead(II) hydroxide are insoluble in water. When such solid reactants are used, lead(II) sulphate can also be formed.
Pb(s) + 2HCl(aq) → PbCl2(s)) + H2(g)
PbCO3(s) + 2HCl(aq) → PbCl2(s) + H2O(l) + CO2(g)
Pb(OH)2(s) + 2HCl(aq) → PbCl2(s) + 2H2O(l)
However, the lead(II) chloride formed is insoluble in the dilute hydrochloride acid, and lead(II) chloride formed becomes a solid layer coated on the surface of the solid reactants. This leads to three disadvantages :
(1) The lead(II) chloride layer separates the solid reactants and the dilute hydrochloric acid, and thus the reaction will slow down and then stop soon after the reaction starts.
(2) The lead(II) chloride layer coats on the surface of the solid reactants, and thus lead(II) chloride formed is impossible separated from the reaction mixture.