A Gaussian sphere of radius 4.00cm is centered on a ball that has a radius of 1.00cm and a uniform charge distribution.The total(net) electric flux through the surface of the Gaussian sphere is +5.60x10^4 (Nxm^2/C).What is the electric potential 12.0cm from the center of the ball??
請物理高手解題一下...我算不出答案來...謝謝︿︿＂
高斯球體題目求電位？
2010-03-25 7:27 am
回答 (1)
2010-03-25 7:41 am
✔ 最佳答案
By Gauss Law,Electric flux = q / E0
q / E0 = 5.60 X 10^4
So, now the electric potential at 12.0 cm from the ball, V
= 1/4piE0 q/r
= (1/4pi)(q/E0)(1/r)
= (1/4pi)(5.60 X 10^4)(1/0.12)
= 3.71 X 10^4 V
參考: Physics king
收錄日期: 2021-04-19 21:45:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100324000010KK10209