f(x)=(x^n)*e^(ax)
find
the 2n-th derivative of f(x) at x=0
any appropriate method can be used
更新1:
there is one way which is within the secondary-school syllabus and gives a much neater solution
更新2:
no.. i don't mean that your solution is quite neat....if you use leibniz's rule, it's like that
更新3:
the one who shares pure maths notes on "little soldier" is you?
更新4:
i really appreciate you! esp. the "past paper analysis" i think that helps students i've glanced through it but i still have no time to read it are you sitting for the coming ALE?
更新5:
http://i256.photobucket.com/albums/hh182/zilu_photo/sshot-2010-03-26-22-11-35.png
