✔ 最佳答案
圖片參考:
http://img221.imageshack.us/img221/6007/maths27.jpg
ㄥDAH = θ , (25° <= θ <= 40°)
ㄥHDB = 60/2 = 30°
;;
HD / 130 = sin θ
i.e. HD = 130 sin θ
(BD/2) / HD = cos30°
BD / 2HD = √3 / 2
BD = (√3)HD
BD = 130√3 sinθ
cosㄥBAD = (AB^2 + AD^2 - BD^2) / (2 AB AD)
cosㄥBAD = (130^2 + 130^2 - (130√3 sinθ)^2) / (2 * 130 * 130)
cosㄥBAD = [33800 - 50700 (sin θ)^2] / 33800
Since sin 25° <= sin θ <= sin 40°
The max. of cosㄥBAD = [33800 - 50700(sin 25°)^2] / 33800
= 0.73209 , min. ㄥBAD = 42.938°
The min. of cosㄥBAD = [33800 - 50700(sin 40°)^2] / 33800
= 0.38024 , max. ㄥBAD = 67.652°
42.938° <= θ <= 67.652°
2010-03-20 17:23:13 補充:
42.938° <= θ <= 67.652°
should be
42.938° <= ㄥBAD <= 67.652°