Find the least value of
(2+sinx)/(2-sinx)
where
0 degree 細過or= x 細過or= 360 degree
trigo 搵 least value
2010-03-20 3:33 pm
回答 (1)
2010-03-20 4:32 pm
✔ 最佳答案
(2+sinx)/(2-sinx)=-(-2-sinx)/(2-sinx)=-[(2-sinx)-4]/(2-sinx)
=4/(2-sinx)-1
4/(2-sinx)-1 is minimum when 4/(2-sinx) is minimum
4/(2-sinx) is minimum when 2-sinx is maximum
2-sinx is maximum when sinx is minimum
So,(2+sinx)/(2-sinx) is minimum when sinx is minimum
the least value of (2+sinx)/(2-sinx)=(2+-1)/(2--1)=1/3
收錄日期: 2021-04-13 17:09:49
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