please explain in detail
you may not need to draw the diagram~
I know how to resolve the forces
the answer is C
but i think statement is correct......
圖片參考:http://i256.photobucket.com/albums/hh182/zilu_photo/sshot-2010-03-16-18-11-53.png
更新1:
Is W.sin(theta) = m.[L sin(theta)].w^2 ? what if I get g=L w^2 sin(theta) and so the statement 1 is correct?
更新2:
If W.sin(theta) = m.[L sin(theta)].w^2 holds, w^2=W/(m L) and cos(theta)=mg/W same conclusion-> 1st statement is true