latent heat question

steam at 100 degree celsius is pumped into an insulated vessel containing 0.2kg of melting ice at 0 degree celsius

(a)what is the mass of steam required to just melt all the ice?
ans: let m be the mass of steam required
m(2.26x10^6)+m(4200)(100-0)=(0.2)(3.34x10^5)
m=0.025 kg
係咪即係佢變左做水之後再由100度既水變成0度既水 = ice melt 既latent heat

(b)If, instead ,0.2kg of steam is pumped into the vessel ,what would you expect
about the final product?Justify your answer with suitable calculation.

ans:The product is a mixture of water and steam at 100 degree C
Latent heat required to melt the ice + heat required to heat melted ice to 100
degree C
Q1=0.2(3.34x10^5)+(0.2)(4200)(100-0)
=150800J
Latent heat that can be released from 0.2kg of steam,
Q2=(0.2)(2.26X10^6)
=452000J
Q1<Q2 ,so the final product is a mixture of water and steam
個latent heat of vapourization 係咪可以係water 轉成steam or steam 轉成water 兩者通用?