化學酸鹼計算

H^+(aq) + NH3(aq) → NH4^+(aq)
不考慮任何解離：
混合後總體積= 50 + 50 = 100 mL
[NH4^+]o = 0.2 x(50/100) = 0.1 M
[NH3]o = 0.4 x (50/100) - 0.2 x(50/100) = 0.1 M

考慮以下解離：
NH3(aq) + H2O(l) = NH4^+(aq) + OH^-(aq)
pOH = pKb - log([NH3]o/[NH4^+]o)
pOH = -log(2 x10^-5) - log(0.1/0.1)
pOH = 4.7
pH = 14 - 4.7 = 9.3