A question of CE Physics
2010-03-16 3:02 am
回答 (1)
2010-03-16 3:31 am
✔ 最佳答案
18.I = P/V
Let n be greatest number of light bulbs without triggering the circuit beaker.
Total current ≤ 15A
(1100/220) + (550/220) + n(100/220) ≤ 15
5 + 2.5 + (5n/11) ≤ 15
5n/11 ≤ 7.5
5n ≤ 82.5
n ≤ 16.5
Hence, the greatest number of light bulbs = 16
參考: 老爺子
收錄日期: 2021-04-13 17:08:50
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