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I suppose you are talking about destructive interference by reflection at the top and bottom of the thin film.
In applying the equation: 2.n.t = (m+1/2)入
the wavelength of light in air 入(air) should be used.
In fact, the above equation comes from the equation,
2t = (m+1/2)入(film)
where 入(film) is the wavelength of light in the material medium of the film
The term on the left hand side, 2t, is the (geometrical) path difference. The wavelength of light at the medium of intereston should be used on the right hand side. In this case, it is the wavelength at the thin film.
Since when light travels in the film, its speed is reduced but keeping the frequency unchanged, hence we have,
v(film) = f.入(film), where v(film) is the speed of light in the film
When light travels in air, we have, v(air) = f.入(air)
Dividing both equations, v(film)/v(air) = 入(film)/入(air)
i.e. 入(film) = 入(air).[v(film)/v(air)] = 入(air)/[v(air)/v(film)] = 入(air)/n
where n = v(air)/v(film), is the refractive index of the film material
Thus, the destructive interference equation becomes,
2t = (m+1/2)[入(air)/n]
i.e. 2nt = (m+1/2)入(air)
[Note: it is assumed that, to a good approximation, the wavelengths of light in air and vacuum are the same].