math Algebra (log)

9. Rewrite as a single logarithm: log8 -1/2logx-2log(y-6).
log8 -1/2logx-2log(y-6)
= log8 - logx^(1/2)-log(y-6)^2
= log8/x^1/2
= log[8/x^(1/2)]/(y-6)^2
= log8(y-6)^2/√x
12. Write log6(3x -4) = y in exponential form.
log6(3x -4) = y
6(3x-4)=10^y
18x-24=10^y



2010-03-12 17:01:30 補充：
the the question should be log_6 (x+3) = y

that's right~
many thanks~

For log_6 (3x-4) = y
3x-4 = 6^y
6^y = 3x-4