From 3 Maths

2010-03-08 4:09 am
complete it by using trigonometric identities
plz show steps
1)cos^3θ+cosθsin^2θ
2)1+1/tan^2θ
3)sinθtanθ+cosθ
4)1-(cosθ+sinθ)^2
5)sin^2θ/1-sin^2θ

回答 (1)

2010-03-08 10:48 pm
✔ 最佳答案
1)cos^3θ+cosθsin^2θ
= cosθ(cos^2θ+sin^2θ)
= cosθ

2)1+1/tan^2θ
= (tan^2θ+1)/tan^2θ
= [(sin^2θ/cos^2θ) + 1]/(sin^2θ/cos^2θ)
= [(sin^2θ + cos^2θ)/cos^2θ]/(sin^2θ/cos^2θ)
= 1/sin^2θ

3)sinθtanθ+cosθ
= (sin^2θ/cosθ) + cosθ
= (sin^2θ + cos^2θ)/cosθ
= 1/cosθ

4)1-(cosθ+sinθ)^2
= 1- (cos^2θ+sin^2θ + 2cosθsinθ)
= -2cosθsinθ

5)sin^2θ/1-sin^2θ
= sin^2θ/cos^2θ
= tan^2θ


收錄日期: 2021-04-13 17:09:13
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