5條5條5條5條5條5條

(2) It should be the point of intersection between y = 1/x + 2 and y = 1, i.e. x = -1

(4) 2x3 - x + 1 = 2x - 1

2x3 - 3x + 2 = 0

(5) 2x2 - 6x - 3 = 0

2(x2 - 2x - 3) - 2x + 3 = 0

2y = 2x - 3

y = x - 3/2

(6) 2x2 - x - 3 = 0

2x2 - x + 1 - 4 = 0

y - 4 = 0

y = 4

(7) 2x2 + kx - 3 = x - 5

2x2 + (k - 1)x + 2 = 0

2[x2 + (k - 1)x/2 + 1] = 0

x2 + (k - 1)x/2 + 1 = 0

(k - 1)/2 = 1

k = 3

都去不到
有什麼方法?

2.C
4.A
5.B
6.B
7.A