In the given multiplication, different letters represent different integers ranging from 0 to 9. Find the value of A + B + C + D
ABCD x 9 = DCBA
有冇人識做呢條數?
2010-03-04 10:47 pm
回答 (1)
2010-03-04 11:13 pm
✔ 最佳答案
ABCD x 9 = DCBAIf A > 1 , ABCD x 9 is a 5 digits number, so A = 1,
If B = 2 or above , 12CD x 9 > 1200 x 9 = 10800 is a 5 digits number,
So B = 0.
The last digit of D x 9 = A = 1 , so D = 9 or 1(rejected since A = 1)
Becomes 10C9 x 9 = 9C01
(1009 + 10*C) x 9 = 9001 + 100*C
9081 + 90*C = 9001 + 100*C
10*C = 80
C = 8
A + B + C + D
= 1 + 0 + 8 + 9
= 18
收錄日期: 2021-04-21 22:12:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100304000051KK00567