maths~~~~~~

2010-03-04 4:41 am
As follows:

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更新1:

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回答 (1)

2010-03-04 5:23 am
✔ 最佳答案

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連BD,連AC,

由PB = PD 得ㄥPDB = ㄥDBP(等腰△底角)

ㄥACD = ㄥDBP(圓內接4邊形對角補角)
ㄥCAB = ㄥPDB

因已證 ㄥPDB = ㄥDBP,
即ㄥACD = ㄥCAB ,

得PA = PC(等腰△兩腰)

AB = PA - PB

CD = PC - PD


即AB = CD


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