maths~~~~~~

2010-03-03 9:46 pm

回答 (1)

2010-03-03 10:01 pm
✔ 最佳答案
BD^2=BC^2+CD^2-2BC*CD*cos(BCD)

=>BD^2=4^2+6^2-2(4)(6)cos(120)

=>BD=8.7178 cm

AD=AB=10 cm givien

cosABD = (BA^2+BD^2-AD^2)/(2BA*BD) =>ABD= 64.15806724

cosDBC = (BD^2+BC^2-DC^2)/(2*BD*BC)=>DBC= 36.5877555

=>ABC = ABD+DBC = 100.7025823

=>AC^2=BC^2+AB^2-2*AB*BCcosABC

=>AC=11.44 cm//


收錄日期: 2021-04-23 20:43:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100303000051KK00499

檢視 Wayback Machine 備份