bn= sin( (nπ) / 2)
更新1:
bn = sin ( (n*pi) / 2)
更新2:
How? can you show me the steps please? Thanks!
Calculus problem
2010-02-25 10:27 pm
State whether this sequence converges or diverges. Explain.
bn= sin( (nπ) / 2)
bn= sin( (nπ) / 2)
回答 (1)
2010-02-25 11:21 pm
✔ 最佳答案
sin (n pi)/2 =1 when n=4k+1, k=1,2,3...So b_n does not tends to 0 and the sequence diverges.
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