Calculus problem

2010-02-25 10:27 pm
State whether this sequence converges or diverges. Explain.

bn= sin( (nπ) / 2)
更新1:

bn = sin ( (n*pi) / 2)

更新2:

How? can you show me the steps please? Thanks!

回答 (1)

2010-02-25 11:21 pm
✔ 最佳答案
sin (n pi)/2 =1 when n=4k+1, k=1,2,3...

So b_n does not tends to 0 and the sequence diverges.


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