a/2+b/3=13
a/3-b/4=3
要用[加減消元法]
唔該曬...
二元一次方程
2010-02-22 8:30 am
回答 (1)
2010-02-22 9:06 am
✔ 最佳答案
a/2+b/3=13....(1)a/3-b/4=3....(2)
(1)*3 + (2)*4 :
3a/2 + b + 4a/3 - b = 39 + 12
3a/2 + 4a/3 = 51
9a + 8a = 51*6
17a = 306
a = 18
代入(1) :
18/2 + b/3 = 13
b/3 = 13 - 9
b = 12
收錄日期: 2021-04-21 22:10:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100222000051KK00056