How do you solve this math equation?

2010-02-21 3:28 pm

1/(x^2) = ax^2

Find a?

回答 (5)

2010-02-21 3:31 pm

✔ 最佳答案

1/(x^2) = ax^2
a = [1/(x^2)]/(x^2)
a = [1/(x^2)][1/(x^2)]
a = 1/(x^4)

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2010-02-21 3:32 pm

1/(x^2) = ax^2
1 = ax^4
x^4 = 1/a
x = Â±1/(4th root of a)

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2010-02-21 3:31 pm

1 = a*(x^2)*(x^2) = a*x^4

x^4 = 1/a

x = (1/a)^1/4

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2010-02-21 3:41 pm

1/(x^2) = ax^2
ax^2(x^2) = 1
ax^4/x^4 = 1/x^4
a=1/x^4

then.. if u have a given for x ...
ex.
assume that x=2

a=1/x^4
a=1/(2)^4
answer: a=1/16

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2010-02-21 3:31 pm

1/x^2=ax^2 /x^2

1/x^4=a

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