1/(x^2) = ax^2
Find a?
How do you solve this math equation?
2010-02-21 3:28 pm
回答 (5)
2010-02-21 3:31 pm
✔ 最佳答案
1/(x^2) = ax^2a = [1/(x^2)]/(x^2)
a = [1/(x^2)][1/(x^2)]
a = 1/(x^4)
2010-02-21 3:32 pm
1/(x^2) = ax^2
1 = ax^4
x^4 = 1/a
x = ±1/(4th root of a)
1 = ax^4
x^4 = 1/a
x = ±1/(4th root of a)
2010-02-21 3:31 pm
1 = a*(x^2)*(x^2) = a*x^4
x^4 = 1/a
x = (1/a)^1/4
x^4 = 1/a
x = (1/a)^1/4
2010-02-21 3:41 pm
1/(x^2) = ax^2
ax^2(x^2) = 1
ax^4/x^4 = 1/x^4
a=1/x^4
then.. if u have a given for x ...
ex.
assume that x=2
a=1/x^4
a=1/(2)^4
answer: a=1/16
ax^2(x^2) = 1
ax^4/x^4 = 1/x^4
a=1/x^4
then.. if u have a given for x ...
ex.
assume that x=2
a=1/x^4
a=1/(2)^4
answer: a=1/16
2010-02-21 3:31 pm
1/x^2=ax^2 /x^2
1/x^4=a
1/x^4=a
收錄日期: 2021-05-01 13:01:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100221072833AANtdte