why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
更新1:
why logx y=logx/logy why logx y=logx/logy why logx y=logx/logy
why logx y=logx/logy
2010-02-22 4:13 am
why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
why logx y=logx/logy
回答 (1)
2010-02-22 7:32 am
✔ 最佳答案
Let u=logx y (with base x)y=x^u
logy=log(x^u) (with base 10)
logy=ulogx
u=logx y=logy/logx
收錄日期: 2021-04-22 00:47:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100221000051KK01590