inequality1

2010-02-22 12:35 am
看圖~~~看圖~~~看圖~~~看圖~~~看圖~~~




圖片參考:http://i256.photobucket.com/albums/hh182/zilu_photo/sshot-2010-02-21-16-33-17.png

回答 (1)

2010-02-22 2:42 am
✔ 最佳答案
0 <=(ai-aj)*(bi-bj)= ai*bi+aj*bj-(ai*bj+aj*bi)
so, ai*bi+aj*bj>= ai*bj+aj*bi
thus, Σ ai*b(n-1+i) <= Σ ai*bi


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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100221000051KK01071

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