1.Calculate the work
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.
the answer is 4poVo.. can you explain it in specific detail.
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2.A 0.5
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(
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.
a)If the original experiment is repeated but 100
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of the 0
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water is replaced with 100
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of 0
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ice, what is the final temperature of the water and block?
b)If the original experiment is repeated but 100
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of the 0
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water is replaced with only 25
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of 0
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ice, what is the final temperature of the water and block?
thermal energy
2010-02-21 12:35 pm
回答 (1)
2010-02-21 7:17 pm
✔ 最佳答案
1. Work done by gas = arear under the curve in the P-V diagramhence, work done = area of trapezium
= [3(Po) + Po].(3Vo - Vo)/2 = (4Po)(2Vo)/2 = 4Po.Vo
2. Let m be thw mass of water
using the heat balance equation,
0.5 x 900 x (200-20) = m.(4186).(20)
m = 0.9675 kg
(a) Heat abosirbed by wtaer and ice
= 0.1 x 334000 + 0.9675 x 4186 x T
where T is the new final temperature, and 334000 is the latent heat of fusion of ice
Heat given out by block
= 0.5 x 900 x (200-T)
hence, 0.1 x 334000 + 0.9675 x 4186 x T = 0.5 x 900 x (200-T)
solve for T gives T = 12.6'C
(b) Calculaton silimar to the above,
0.025 x 334000 + 0.8925 x 4186 x T = 0.5 x 900 x (200-T)
solve for T gives T = 19.5'C
solve for T gives T =
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