-30p^3+8p^2+8p factor completely?

2010-02-18 4:10 pm
factor completely

回答 (7)

2010-02-18 4:52 pm
✔ 最佳答案
-30p^3 + 8p^2 + 8p
= -p(30p^2 - 8p - 8)
= -2p(15p^2 - 4p - 4)
= -2p(15p^2 + 6p - 10p - 4)
= -2p[(15p^2 + 6p) - (10p + 4)]
= -2p[3p(5p + 2) - 2(5p + 2)]
= -2p(5p + 2)(3p - 2)
2010-02-19 12:34 am
First of all, look for a common factor. In this case, there is one and it's -2P.

Now, take -2P(15P^2 - 4P - 4). But, you can still factor what's in parentheses as follows:
(3P - 2)(5P + 2) Now don't forget you can't just abandon the original common factor, -2P. To complete this you simply arrange the problem like so:

Answer: -2P(3P - 2)(5P + 2)

**TIP** ALWAYS go back and check your work by multiplying. It only takes a few seconds and it will help you catch careless errors that we all make. If you follow the order of operations multiply the answer above you will find that you end up with the original equation.
2010-02-19 12:27 am
You can always make a good use of homework assistance services, for example

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Save yourself for more important tasks. :)
2010-02-19 12:19 am
-30p³ + 8p² + 8p = -2p(15p² - 4p - 4)

p = [-(-4) ± √((-4)² - 4(15)(-4))] / (2·15)
   = [4 ± √(256)] / 30
   = [4 ± 16] / 30
   = 12/30, 20/30
   = -0.4, ⅔

-30p³ + 8p² + 8p = -2p(15p² - 4p - 4)
= -2p·15(p+0.4)(p-⅔)
= -2p(5p+2)(3p-2)
= 2p(2+5p)(2-3p)
2010-02-19 12:18 am
Hi there

How about 2p ( –5p – 2 ) ( 3p – 2 )

☺
2010-02-19 12:15 am
remove greatest common factor by putting it outside the parenthesis:
2p (-15p^2 + 4p + 4)

now factor out (-15p^2 + 4p + 4):
(-3p + 2) (5p + 2)
2010-02-19 12:15 am
- 2*p*(5*p + 2)*(3*p - 2)
參考: Maple 13.01


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