8^x+2 = 2^2x+1 / 4^1-x
答案：x=7
求步驟
指數方程一條問題！
2010-02-18 6:39 am
回答 (1)
2010-02-18 6:47 am
✔ 最佳答案
8^(x+2) = 2^(2x+1) / 4^(1-x)(2^3)^(x+2) = 2^(2x+1) / (2^2)^(1-x)
2^(3x+6) = 2^(2x+1) / 2^(2-2x)
2^(3x+6) = 2 ^ [ (2x+1) - (2-2x) ]
2^(3x + 6) = 2 ^ (4x - 1)
3x + 6 = 4x - 1
x = 7
收錄日期: 2021-04-21 22:08:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100217000051KK01505