2L of concentrated HCl (10mol/L) are spilled in a laboratory accident. Solid sodium bicarbonate was used to neutralise the spilled acid.
Q) Calculate the minimum mass of sodium bicarbonate needed to completely neutralise the spilled acid.
chem- neutralization
2010-02-14 7:58 pm
回答 (1)
2010-02-14 8:09 pm
✔ 最佳答案
From the equation NaHCO3 + HCl → NaCl + H2O + CO21 mole of HCl needs 1 mole of NaHCO3 for complete neutralization.
So no. of moles of HCl = No. of moles of NaHCO3 = 2 x 10 = 20
Thus, mass of NaHCO3 needed = 20 x (23 + 1 + 12 + 3 x 16) = 1680 g
參考: Myself
收錄日期: 2021-04-27 15:03:42
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