1) '1^3+3^3+5^3+...+(2n-1)^3=n^2(2n^2 - 1)"
2)'1/(1*3)+1/(3*5)+1/(5*7)+...+1/[(2n-1)(2n+1)=n/(2n+1)
3)1^2/(1*3)+2^2/(3*5)+...+n^2/[(2n-1)(2n+1)]
可5可以教我計既技考?
我次次let左n=k+1之後,
都計5到L.H.S.=R.H.S.
點樣易d計到??
更新1:
3)1^2/(1*3)+2^2/(3*5)+...+n^2/[(2n-1)(2n+1)]=n(n+1)/2(2n+1)
