Solve x^2-x-30=0 using steps.?

X^2-x-30=0

a b c

a=1 b=-1 c= -30

"c" is a product of two factors, while b is the sum of the factors so check your factors of 30
which are:

30 times 1
15 times 2
10 times 3
5 times 6

The factors' sum should give you -1x (or b as labeled above). The only factor which will work 5 and 6. So how does 5 and 6 equal -1? Well you have to adjust the signs (+/-) so this will work. So positive 5 + -(6) gives you -1.

You write it like this.

(x+5)(x-6)=0

Now when you solve for x, you have to switch the signs again, everything which was negative, turns positive and vice versa.

so x= either -6 or +5.

These x-values are the values at which y=0, so the line crosses the x-axis (x-intercept). Seeing that it is to the power of 2 tells you that you have 2 x values, if it's cubic (to the 3rd power) you will have three...and so on.

Hope this helps,

M. Desinger

a) 4x2 -14x -30 = 0 8 - 14x -30 = 0 combine like words.. 8-30 is -22.. so 14x = -22 divide the two sides by technique of 14 to get x by technique of itself x = -a million.fifty seven i do no longer know approximately B because of the fact does x2 recommend x situations 2 or x squared?

( x - 6 ) ( x + 5 ) = 0

x = 6 , x = - 5

Question Number 1 :
For this equation x^2 - x - 30 = 0 , answer the following questions :
A. Find the roots using Quadratic Formula !

Answer Number 1 :
The equation x^2 - x - 30 = 0 is already in a*x^2+b*x+c=0 form.
So we can imply that the value of a = 1, b = -1, c = -30.

1A. Find the roots using Quadratic Formula !
Use the formula,
x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a)
As we know that a = 1, b = -1 and c = -30,
we just need to subtitute the value of a,b and c in the abc formula.
Which produce x1 = (-(-1) + sqrt( (-1)^2 - 4 * (1)*(-30)))/(2*1) and x2 = (-(-1) - sqrt( (-1)^2 - 4 * (1)*(-30)))/(2*1)
Which can be turned into x1 = ( 1 + sqrt( 1+120))/(2) and x2 = ( 1 - sqrt( 1+120))/(2)
Which is the same with x1 = ( 1 + sqrt( 121))/(2) and x2 = ( 1 - sqrt( 121))/(2)
We got x1 = ( 1 + 11 )/(2) and x2 = ( 1 - 11 )/(2)
We get following answers x1 = 6 and x2 = -5

x^2 - x - 30 = 0
x^2 + 5x - 6x - 30 = 0
(x^2 + 5x) - (6x + 30) = 0
x(x + 5) - 6(x + 5) = 0
(x + 5)(x - 6) = 0

x + 5 = 0
x = -5

x - 6 = 0
x = 6

∴ x = -5 or 6

( x ) ( x ) = 0 /// x*x = x^2
( x - 6 ) ( x + 5 ) = 0 /// Find two numbers that have a product -30 and a sum of -1. ///// -6 * 5

(x-6)(x + 5)=0
x=6
x= -5
Good night!

x^2-x-30=0
x^2-6x+5x-30=0
x(x-6)+5(x-6)=0
(x+5)(x-6)=0
x=-5,6