By considering f'(x),prove that f(x)>0 for 0<x<pi
更新1:
by considering f ' (x),prove that f(x) > 0 for 0 < x < pi
唔識微分一小題,快
2010-02-12 3:01 am
let f(x)=sin x-xcos x
By considering f'(x),prove that f(x)>0 for 0<x<pi
By considering f'(x),prove that f(x)>0 for 0<x<pi
回答 (1)
2010-02-12 4:01 am
✔ 最佳答案
f'(x)=cosx+xsinx-cosx=xsinx which is larger than or equal to 0 when 0<x<piSo f(x) is a monotonic increasing function on (0,pi) and
f(x) > f(0)=0
收錄日期: 2021-04-26 13:59:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100211000051KK01481