maths

2010-02-10 2:04 am
remainder=10x+17 quotient=x-6 dividend=x^3-4x^2+x-1 please find the
divisor.

thx.

回答 (2)

2010-02-10 2:14 am
✔ 最佳答案
divisor x quotient + remainder = dividend
divisor * (x-6) + 10x+17 = x^3 - 4x^2 + x - 1
divisor * (x-6) = x^3 - 4x^2 + x - 1 - 10x - 17 = x^3 - 4x^2 - 9x - 18
divisor = (x^3 - 4x^2 - 9x - 18) / (x - 6)

6] 1 - 4 - 9 - 18
+. .....6..12...18
------------------------
.....1 +2 +3..+0

divisor = x^2 + 2x + 3

2010-02-09 18:33:32 補充:
synthetic Division (綜合除法)

6] -----> x - 6

1 - 4 - 9 - 18 ------>(x^3 - 4x^2 - 9x - 18)

1 照寫

6*1 = 6

- 4 + 6 = + 2

;

6*2 = 12

-9+12 = +3

.........
2010-02-10 2:17 am
6] 1 - 4 - 9 - 18

+. .....6..12...18
------------------------
.....1 +2 +3..+0


what is this?


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