ratio

1. x^2 = y^3

x = y^(3/2)

So, x : y

= y^(3/2) : y

= y^(1/2) : 1


2. 8^x = 2^y

log(8^x) = log(2^y)

xlog8 = ylog2

xlog(2^3) = ylog2

3xlog2 = ylog2

3x = y

x : y = 1 : 3

1. Wrong Question

2. 8^x=2^y

both side take log , we have xlog8=ylog2

and xlog(2^3)=ylog2

=>3xlog2=ylog2

=3x=y

=>x/y=1/3

=>x:y=1:3//